Integrand size = 16, antiderivative size = 215 \[ \int x^7 (a+b x)^{10} (A+B x) \, dx=-\frac {a^7 (A b-a B) (a+b x)^{11}}{11 b^9}+\frac {a^6 (7 A b-8 a B) (a+b x)^{12}}{12 b^9}-\frac {7 a^5 (3 A b-4 a B) (a+b x)^{13}}{13 b^9}+\frac {a^4 (5 A b-8 a B) (a+b x)^{14}}{2 b^9}-\frac {7 a^3 (A b-2 a B) (a+b x)^{15}}{3 b^9}+\frac {7 a^2 (3 A b-8 a B) (a+b x)^{16}}{16 b^9}-\frac {7 a (A b-4 a B) (a+b x)^{17}}{17 b^9}+\frac {(A b-8 a B) (a+b x)^{18}}{18 b^9}+\frac {B (a+b x)^{19}}{19 b^9} \]
-1/11*a^7*(A*b-B*a)*(b*x+a)^11/b^9+1/12*a^6*(7*A*b-8*B*a)*(b*x+a)^12/b^9-7 /13*a^5*(3*A*b-4*B*a)*(b*x+a)^13/b^9+1/2*a^4*(5*A*b-8*B*a)*(b*x+a)^14/b^9- 7/3*a^3*(A*b-2*B*a)*(b*x+a)^15/b^9+7/16*a^2*(3*A*b-8*B*a)*(b*x+a)^16/b^9-7 /17*a*(A*b-4*B*a)*(b*x+a)^17/b^9+1/18*(A*b-8*B*a)*(b*x+a)^18/b^9+1/19*B*(b *x+a)^19/b^9
Time = 0.02 (sec) , antiderivative size = 227, normalized size of antiderivative = 1.06 \[ \int x^7 (a+b x)^{10} (A+B x) \, dx=\frac {1}{8} a^{10} A x^8+\frac {1}{9} a^9 (10 A b+a B) x^9+\frac {1}{2} a^8 b (9 A b+2 a B) x^{10}+\frac {15}{11} a^7 b^2 (8 A b+3 a B) x^{11}+\frac {5}{2} a^6 b^3 (7 A b+4 a B) x^{12}+\frac {42}{13} a^5 b^4 (6 A b+5 a B) x^{13}+3 a^4 b^5 (5 A b+6 a B) x^{14}+2 a^3 b^6 (4 A b+7 a B) x^{15}+\frac {15}{16} a^2 b^7 (3 A b+8 a B) x^{16}+\frac {5}{17} a b^8 (2 A b+9 a B) x^{17}+\frac {1}{18} b^9 (A b+10 a B) x^{18}+\frac {1}{19} b^{10} B x^{19} \]
(a^10*A*x^8)/8 + (a^9*(10*A*b + a*B)*x^9)/9 + (a^8*b*(9*A*b + 2*a*B)*x^10) /2 + (15*a^7*b^2*(8*A*b + 3*a*B)*x^11)/11 + (5*a^6*b^3*(7*A*b + 4*a*B)*x^1 2)/2 + (42*a^5*b^4*(6*A*b + 5*a*B)*x^13)/13 + 3*a^4*b^5*(5*A*b + 6*a*B)*x^ 14 + 2*a^3*b^6*(4*A*b + 7*a*B)*x^15 + (15*a^2*b^7*(3*A*b + 8*a*B)*x^16)/16 + (5*a*b^8*(2*A*b + 9*a*B)*x^17)/17 + (b^9*(A*b + 10*a*B)*x^18)/18 + (b^1 0*B*x^19)/19
Time = 0.41 (sec) , antiderivative size = 215, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {85, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int x^7 (a+b x)^{10} (A+B x) \, dx\) |
| \(\Big \downarrow \) 85 |
| \(\displaystyle \int \left (\frac {a^7 (a+b x)^{10} (a B-A b)}{b^8}-\frac {a^6 (a+b x)^{11} (8 a B-7 A b)}{b^8}+\frac {7 a^5 (a+b x)^{12} (4 a B-3 A b)}{b^8}-\frac {7 a^4 (a+b x)^{13} (8 a B-5 A b)}{b^8}+\frac {35 a^3 (a+b x)^{14} (2 a B-A b)}{b^8}-\frac {7 a^2 (a+b x)^{15} (8 a B-3 A b)}{b^8}+\frac {(a+b x)^{17} (A b-8 a B)}{b^8}+\frac {7 a (a+b x)^{16} (4 a B-A b)}{b^8}+\frac {B (a+b x)^{18}}{b^8}\right )dx\) |
| \(\Big \downarrow \) 2009 |
| \(\displaystyle -\frac {a^7 (a+b x)^{11} (A b-a B)}{11 b^9}+\frac {a^6 (a+b x)^{12} (7 A b-8 a B)}{12 b^9}-\frac {7 a^5 (a+b x)^{13} (3 A b-4 a B)}{13 b^9}+\frac {a^4 (a+b x)^{14} (5 A b-8 a B)}{2 b^9}-\frac {7 a^3 (a+b x)^{15} (A b-2 a B)}{3 b^9}+\frac {7 a^2 (a+b x)^{16} (3 A b-8 a B)}{16 b^9}+\frac {(a+b x)^{18} (A b-8 a B)}{18 b^9}-\frac {7 a (a+b x)^{17} (A b-4 a B)}{17 b^9}+\frac {B (a+b x)^{19}}{19 b^9}\) |
-1/11*(a^7*(A*b - a*B)*(a + b*x)^11)/b^9 + (a^6*(7*A*b - 8*a*B)*(a + b*x)^ 12)/(12*b^9) - (7*a^5*(3*A*b - 4*a*B)*(a + b*x)^13)/(13*b^9) + (a^4*(5*A*b - 8*a*B)*(a + b*x)^14)/(2*b^9) - (7*a^3*(A*b - 2*a*B)*(a + b*x)^15)/(3*b^ 9) + (7*a^2*(3*A*b - 8*a*B)*(a + b*x)^16)/(16*b^9) - (7*a*(A*b - 4*a*B)*(a + b*x)^17)/(17*b^9) + ((A*b - 8*a*B)*(a + b*x)^18)/(18*b^9) + (B*(a + b*x )^19)/(19*b^9)
3.2.40.3.1 Defintions of rubi rules used
Int[((d_.)*(x_))^(n_.)*((a_) + (b_.)*(x_))*((e_) + (f_.)*(x_))^(p_.), x_] : > Int[ExpandIntegrand[(a + b*x)*(d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, d, e, f, n}, x] && IGtQ[p, 0] && (NeQ[n, -1] || EqQ[p, 1]) && NeQ[b*e + a* f, 0] && ( !IntegerQ[n] || LtQ[9*p + 5*n, 0] || GeQ[n + p + 1, 0] || (GeQ[n + p + 2, 0] && RationalQ[a, b, d, e, f])) && (NeQ[n + p + 3, 0] || EqQ[p, 1])
Time = 0.40 (sec) , antiderivative size = 235, normalized size of antiderivative = 1.09
| method | result | size |
| norman | \(\frac {a^{10} A \,x^{8}}{8}+\left (\frac {10}{9} a^{9} b A +\frac {1}{9} a^{10} B \right ) x^{9}+\left (\frac {9}{2} a^{8} b^{2} A +a^{9} b B \right ) x^{10}+\left (\frac {120}{11} a^{7} b^{3} A +\frac {45}{11} a^{8} b^{2} B \right ) x^{11}+\left (\frac {35}{2} a^{6} b^{4} A +10 a^{7} b^{3} B \right ) x^{12}+\left (\frac {252}{13} a^{5} b^{5} A +\frac {210}{13} a^{6} b^{4} B \right ) x^{13}+\left (15 a^{4} b^{6} A +18 a^{5} b^{5} B \right ) x^{14}+\left (8 a^{3} b^{7} A +14 a^{4} b^{6} B \right ) x^{15}+\left (\frac {45}{16} a^{2} b^{8} A +\frac {15}{2} a^{3} b^{7} B \right ) x^{16}+\left (\frac {10}{17} a \,b^{9} A +\frac {45}{17} a^{2} b^{8} B \right ) x^{17}+\left (\frac {1}{18} b^{10} A +\frac {5}{9} a \,b^{9} B \right ) x^{18}+\frac {b^{10} B \,x^{19}}{19}\) | \(235\) |
| default | \(\frac {b^{10} B \,x^{19}}{19}+\frac {\left (b^{10} A +10 a \,b^{9} B \right ) x^{18}}{18}+\frac {\left (10 a \,b^{9} A +45 a^{2} b^{8} B \right ) x^{17}}{17}+\frac {\left (45 a^{2} b^{8} A +120 a^{3} b^{7} B \right ) x^{16}}{16}+\frac {\left (120 a^{3} b^{7} A +210 a^{4} b^{6} B \right ) x^{15}}{15}+\frac {\left (210 a^{4} b^{6} A +252 a^{5} b^{5} B \right ) x^{14}}{14}+\frac {\left (252 a^{5} b^{5} A +210 a^{6} b^{4} B \right ) x^{13}}{13}+\frac {\left (210 a^{6} b^{4} A +120 a^{7} b^{3} B \right ) x^{12}}{12}+\frac {\left (120 a^{7} b^{3} A +45 a^{8} b^{2} B \right ) x^{11}}{11}+\frac {\left (45 a^{8} b^{2} A +10 a^{9} b B \right ) x^{10}}{10}+\frac {\left (10 a^{9} b A +a^{10} B \right ) x^{9}}{9}+\frac {a^{10} A \,x^{8}}{8}\) | \(244\) |
| gosper | \(\frac {1}{8} a^{10} A \,x^{8}+\frac {10}{9} x^{9} a^{9} b A +\frac {1}{9} x^{9} a^{10} B +\frac {9}{2} x^{10} a^{8} b^{2} A +x^{10} a^{9} b B +\frac {120}{11} x^{11} a^{7} b^{3} A +\frac {45}{11} x^{11} a^{8} b^{2} B +\frac {35}{2} x^{12} a^{6} b^{4} A +10 x^{12} a^{7} b^{3} B +\frac {252}{13} x^{13} a^{5} b^{5} A +\frac {210}{13} x^{13} a^{6} b^{4} B +15 A \,a^{4} b^{6} x^{14}+18 B \,a^{5} b^{5} x^{14}+8 A \,a^{3} b^{7} x^{15}+14 B \,a^{4} b^{6} x^{15}+\frac {45}{16} x^{16} a^{2} b^{8} A +\frac {15}{2} x^{16} a^{3} b^{7} B +\frac {10}{17} x^{17} a \,b^{9} A +\frac {45}{17} x^{17} a^{2} b^{8} B +\frac {1}{18} x^{18} b^{10} A +\frac {5}{9} x^{18} a \,b^{9} B +\frac {1}{19} b^{10} B \,x^{19}\) | \(245\) |
| risch | \(\frac {1}{8} a^{10} A \,x^{8}+\frac {10}{9} x^{9} a^{9} b A +\frac {1}{9} x^{9} a^{10} B +\frac {9}{2} x^{10} a^{8} b^{2} A +x^{10} a^{9} b B +\frac {120}{11} x^{11} a^{7} b^{3} A +\frac {45}{11} x^{11} a^{8} b^{2} B +\frac {35}{2} x^{12} a^{6} b^{4} A +10 x^{12} a^{7} b^{3} B +\frac {252}{13} x^{13} a^{5} b^{5} A +\frac {210}{13} x^{13} a^{6} b^{4} B +15 A \,a^{4} b^{6} x^{14}+18 B \,a^{5} b^{5} x^{14}+8 A \,a^{3} b^{7} x^{15}+14 B \,a^{4} b^{6} x^{15}+\frac {45}{16} x^{16} a^{2} b^{8} A +\frac {15}{2} x^{16} a^{3} b^{7} B +\frac {10}{17} x^{17} a \,b^{9} A +\frac {45}{17} x^{17} a^{2} b^{8} B +\frac {1}{18} x^{18} b^{10} A +\frac {5}{9} x^{18} a \,b^{9} B +\frac {1}{19} b^{10} B \,x^{19}\) | \(245\) |
| parallelrisch | \(\frac {1}{8} a^{10} A \,x^{8}+\frac {10}{9} x^{9} a^{9} b A +\frac {1}{9} x^{9} a^{10} B +\frac {9}{2} x^{10} a^{8} b^{2} A +x^{10} a^{9} b B +\frac {120}{11} x^{11} a^{7} b^{3} A +\frac {45}{11} x^{11} a^{8} b^{2} B +\frac {35}{2} x^{12} a^{6} b^{4} A +10 x^{12} a^{7} b^{3} B +\frac {252}{13} x^{13} a^{5} b^{5} A +\frac {210}{13} x^{13} a^{6} b^{4} B +15 A \,a^{4} b^{6} x^{14}+18 B \,a^{5} b^{5} x^{14}+8 A \,a^{3} b^{7} x^{15}+14 B \,a^{4} b^{6} x^{15}+\frac {45}{16} x^{16} a^{2} b^{8} A +\frac {15}{2} x^{16} a^{3} b^{7} B +\frac {10}{17} x^{17} a \,b^{9} A +\frac {45}{17} x^{17} a^{2} b^{8} B +\frac {1}{18} x^{18} b^{10} A +\frac {5}{9} x^{18} a \,b^{9} B +\frac {1}{19} b^{10} B \,x^{19}\) | \(245\) |
1/8*a^10*A*x^8+(10/9*a^9*b*A+1/9*a^10*B)*x^9+(9/2*a^8*b^2*A+a^9*b*B)*x^10+ (120/11*a^7*b^3*A+45/11*a^8*b^2*B)*x^11+(35/2*a^6*b^4*A+10*a^7*b^3*B)*x^12 +(252/13*a^5*b^5*A+210/13*a^6*b^4*B)*x^13+(15*A*a^4*b^6+18*B*a^5*b^5)*x^14 +(8*A*a^3*b^7+14*B*a^4*b^6)*x^15+(45/16*a^2*b^8*A+15/2*a^3*b^7*B)*x^16+(10 /17*a*b^9*A+45/17*a^2*b^8*B)*x^17+(1/18*b^10*A+5/9*a*b^9*B)*x^18+1/19*b^10 *B*x^19
Time = 0.22 (sec) , antiderivative size = 243, normalized size of antiderivative = 1.13 \[ \int x^7 (a+b x)^{10} (A+B x) \, dx=\frac {1}{19} \, B b^{10} x^{19} + \frac {1}{8} \, A a^{10} x^{8} + \frac {1}{18} \, {\left (10 \, B a b^{9} + A b^{10}\right )} x^{18} + \frac {5}{17} \, {\left (9 \, B a^{2} b^{8} + 2 \, A a b^{9}\right )} x^{17} + \frac {15}{16} \, {\left (8 \, B a^{3} b^{7} + 3 \, A a^{2} b^{8}\right )} x^{16} + 2 \, {\left (7 \, B a^{4} b^{6} + 4 \, A a^{3} b^{7}\right )} x^{15} + 3 \, {\left (6 \, B a^{5} b^{5} + 5 \, A a^{4} b^{6}\right )} x^{14} + \frac {42}{13} \, {\left (5 \, B a^{6} b^{4} + 6 \, A a^{5} b^{5}\right )} x^{13} + \frac {5}{2} \, {\left (4 \, B a^{7} b^{3} + 7 \, A a^{6} b^{4}\right )} x^{12} + \frac {15}{11} \, {\left (3 \, B a^{8} b^{2} + 8 \, A a^{7} b^{3}\right )} x^{11} + \frac {1}{2} \, {\left (2 \, B a^{9} b + 9 \, A a^{8} b^{2}\right )} x^{10} + \frac {1}{9} \, {\left (B a^{10} + 10 \, A a^{9} b\right )} x^{9} \]
1/19*B*b^10*x^19 + 1/8*A*a^10*x^8 + 1/18*(10*B*a*b^9 + A*b^10)*x^18 + 5/17 *(9*B*a^2*b^8 + 2*A*a*b^9)*x^17 + 15/16*(8*B*a^3*b^7 + 3*A*a^2*b^8)*x^16 + 2*(7*B*a^4*b^6 + 4*A*a^3*b^7)*x^15 + 3*(6*B*a^5*b^5 + 5*A*a^4*b^6)*x^14 + 42/13*(5*B*a^6*b^4 + 6*A*a^5*b^5)*x^13 + 5/2*(4*B*a^7*b^3 + 7*A*a^6*b^4)* x^12 + 15/11*(3*B*a^8*b^2 + 8*A*a^7*b^3)*x^11 + 1/2*(2*B*a^9*b + 9*A*a^8*b ^2)*x^10 + 1/9*(B*a^10 + 10*A*a^9*b)*x^9
Time = 0.04 (sec) , antiderivative size = 262, normalized size of antiderivative = 1.22 \[ \int x^7 (a+b x)^{10} (A+B x) \, dx=\frac {A a^{10} x^{8}}{8} + \frac {B b^{10} x^{19}}{19} + x^{18} \left (\frac {A b^{10}}{18} + \frac {5 B a b^{9}}{9}\right ) + x^{17} \cdot \left (\frac {10 A a b^{9}}{17} + \frac {45 B a^{2} b^{8}}{17}\right ) + x^{16} \cdot \left (\frac {45 A a^{2} b^{8}}{16} + \frac {15 B a^{3} b^{7}}{2}\right ) + x^{15} \cdot \left (8 A a^{3} b^{7} + 14 B a^{4} b^{6}\right ) + x^{14} \cdot \left (15 A a^{4} b^{6} + 18 B a^{5} b^{5}\right ) + x^{13} \cdot \left (\frac {252 A a^{5} b^{5}}{13} + \frac {210 B a^{6} b^{4}}{13}\right ) + x^{12} \cdot \left (\frac {35 A a^{6} b^{4}}{2} + 10 B a^{7} b^{3}\right ) + x^{11} \cdot \left (\frac {120 A a^{7} b^{3}}{11} + \frac {45 B a^{8} b^{2}}{11}\right ) + x^{10} \cdot \left (\frac {9 A a^{8} b^{2}}{2} + B a^{9} b\right ) + x^{9} \cdot \left (\frac {10 A a^{9} b}{9} + \frac {B a^{10}}{9}\right ) \]
A*a**10*x**8/8 + B*b**10*x**19/19 + x**18*(A*b**10/18 + 5*B*a*b**9/9) + x* *17*(10*A*a*b**9/17 + 45*B*a**2*b**8/17) + x**16*(45*A*a**2*b**8/16 + 15*B *a**3*b**7/2) + x**15*(8*A*a**3*b**7 + 14*B*a**4*b**6) + x**14*(15*A*a**4* b**6 + 18*B*a**5*b**5) + x**13*(252*A*a**5*b**5/13 + 210*B*a**6*b**4/13) + x**12*(35*A*a**6*b**4/2 + 10*B*a**7*b**3) + x**11*(120*A*a**7*b**3/11 + 4 5*B*a**8*b**2/11) + x**10*(9*A*a**8*b**2/2 + B*a**9*b) + x**9*(10*A*a**9*b /9 + B*a**10/9)
Time = 0.19 (sec) , antiderivative size = 243, normalized size of antiderivative = 1.13 \[ \int x^7 (a+b x)^{10} (A+B x) \, dx=\frac {1}{19} \, B b^{10} x^{19} + \frac {1}{8} \, A a^{10} x^{8} + \frac {1}{18} \, {\left (10 \, B a b^{9} + A b^{10}\right )} x^{18} + \frac {5}{17} \, {\left (9 \, B a^{2} b^{8} + 2 \, A a b^{9}\right )} x^{17} + \frac {15}{16} \, {\left (8 \, B a^{3} b^{7} + 3 \, A a^{2} b^{8}\right )} x^{16} + 2 \, {\left (7 \, B a^{4} b^{6} + 4 \, A a^{3} b^{7}\right )} x^{15} + 3 \, {\left (6 \, B a^{5} b^{5} + 5 \, A a^{4} b^{6}\right )} x^{14} + \frac {42}{13} \, {\left (5 \, B a^{6} b^{4} + 6 \, A a^{5} b^{5}\right )} x^{13} + \frac {5}{2} \, {\left (4 \, B a^{7} b^{3} + 7 \, A a^{6} b^{4}\right )} x^{12} + \frac {15}{11} \, {\left (3 \, B a^{8} b^{2} + 8 \, A a^{7} b^{3}\right )} x^{11} + \frac {1}{2} \, {\left (2 \, B a^{9} b + 9 \, A a^{8} b^{2}\right )} x^{10} + \frac {1}{9} \, {\left (B a^{10} + 10 \, A a^{9} b\right )} x^{9} \]
1/19*B*b^10*x^19 + 1/8*A*a^10*x^8 + 1/18*(10*B*a*b^9 + A*b^10)*x^18 + 5/17 *(9*B*a^2*b^8 + 2*A*a*b^9)*x^17 + 15/16*(8*B*a^3*b^7 + 3*A*a^2*b^8)*x^16 + 2*(7*B*a^4*b^6 + 4*A*a^3*b^7)*x^15 + 3*(6*B*a^5*b^5 + 5*A*a^4*b^6)*x^14 + 42/13*(5*B*a^6*b^4 + 6*A*a^5*b^5)*x^13 + 5/2*(4*B*a^7*b^3 + 7*A*a^6*b^4)* x^12 + 15/11*(3*B*a^8*b^2 + 8*A*a^7*b^3)*x^11 + 1/2*(2*B*a^9*b + 9*A*a^8*b ^2)*x^10 + 1/9*(B*a^10 + 10*A*a^9*b)*x^9
Time = 0.30 (sec) , antiderivative size = 244, normalized size of antiderivative = 1.13 \[ \int x^7 (a+b x)^{10} (A+B x) \, dx=\frac {1}{19} \, B b^{10} x^{19} + \frac {5}{9} \, B a b^{9} x^{18} + \frac {1}{18} \, A b^{10} x^{18} + \frac {45}{17} \, B a^{2} b^{8} x^{17} + \frac {10}{17} \, A a b^{9} x^{17} + \frac {15}{2} \, B a^{3} b^{7} x^{16} + \frac {45}{16} \, A a^{2} b^{8} x^{16} + 14 \, B a^{4} b^{6} x^{15} + 8 \, A a^{3} b^{7} x^{15} + 18 \, B a^{5} b^{5} x^{14} + 15 \, A a^{4} b^{6} x^{14} + \frac {210}{13} \, B a^{6} b^{4} x^{13} + \frac {252}{13} \, A a^{5} b^{5} x^{13} + 10 \, B a^{7} b^{3} x^{12} + \frac {35}{2} \, A a^{6} b^{4} x^{12} + \frac {45}{11} \, B a^{8} b^{2} x^{11} + \frac {120}{11} \, A a^{7} b^{3} x^{11} + B a^{9} b x^{10} + \frac {9}{2} \, A a^{8} b^{2} x^{10} + \frac {1}{9} \, B a^{10} x^{9} + \frac {10}{9} \, A a^{9} b x^{9} + \frac {1}{8} \, A a^{10} x^{8} \]
1/19*B*b^10*x^19 + 5/9*B*a*b^9*x^18 + 1/18*A*b^10*x^18 + 45/17*B*a^2*b^8*x ^17 + 10/17*A*a*b^9*x^17 + 15/2*B*a^3*b^7*x^16 + 45/16*A*a^2*b^8*x^16 + 14 *B*a^4*b^6*x^15 + 8*A*a^3*b^7*x^15 + 18*B*a^5*b^5*x^14 + 15*A*a^4*b^6*x^14 + 210/13*B*a^6*b^4*x^13 + 252/13*A*a^5*b^5*x^13 + 10*B*a^7*b^3*x^12 + 35/ 2*A*a^6*b^4*x^12 + 45/11*B*a^8*b^2*x^11 + 120/11*A*a^7*b^3*x^11 + B*a^9*b* x^10 + 9/2*A*a^8*b^2*x^10 + 1/9*B*a^10*x^9 + 10/9*A*a^9*b*x^9 + 1/8*A*a^10 *x^8
Time = 0.09 (sec) , antiderivative size = 211, normalized size of antiderivative = 0.98 \[ \int x^7 (a+b x)^{10} (A+B x) \, dx=x^9\,\left (\frac {B\,a^{10}}{9}+\frac {10\,A\,b\,a^9}{9}\right )+x^{18}\,\left (\frac {A\,b^{10}}{18}+\frac {5\,B\,a\,b^9}{9}\right )+\frac {A\,a^{10}\,x^8}{8}+\frac {B\,b^{10}\,x^{19}}{19}+\frac {15\,a^7\,b^2\,x^{11}\,\left (8\,A\,b+3\,B\,a\right )}{11}+\frac {5\,a^6\,b^3\,x^{12}\,\left (7\,A\,b+4\,B\,a\right )}{2}+\frac {42\,a^5\,b^4\,x^{13}\,\left (6\,A\,b+5\,B\,a\right )}{13}+3\,a^4\,b^5\,x^{14}\,\left (5\,A\,b+6\,B\,a\right )+2\,a^3\,b^6\,x^{15}\,\left (4\,A\,b+7\,B\,a\right )+\frac {15\,a^2\,b^7\,x^{16}\,\left (3\,A\,b+8\,B\,a\right )}{16}+\frac {a^8\,b\,x^{10}\,\left (9\,A\,b+2\,B\,a\right )}{2}+\frac {5\,a\,b^8\,x^{17}\,\left (2\,A\,b+9\,B\,a\right )}{17} \]
x^9*((B*a^10)/9 + (10*A*a^9*b)/9) + x^18*((A*b^10)/18 + (5*B*a*b^9)/9) + ( A*a^10*x^8)/8 + (B*b^10*x^19)/19 + (15*a^7*b^2*x^11*(8*A*b + 3*B*a))/11 + (5*a^6*b^3*x^12*(7*A*b + 4*B*a))/2 + (42*a^5*b^4*x^13*(6*A*b + 5*B*a))/13 + 3*a^4*b^5*x^14*(5*A*b + 6*B*a) + 2*a^3*b^6*x^15*(4*A*b + 7*B*a) + (15*a^ 2*b^7*x^16*(3*A*b + 8*B*a))/16 + (a^8*b*x^10*(9*A*b + 2*B*a))/2 + (5*a*b^8 *x^17*(2*A*b + 9*B*a))/17